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In 1008, there are 251 working days in USA (Federal holidays).
This is calculated from:
Because 1008 is a leap year, it has 366 days.
Let's remove 53 saturdays and 53 sundays. It remains 261 days.
Now, let's remove 10 public holidays that do not fall during a weekend and we obtain 251 working days in 1008.
There are 251 working days in 1008 in USA (Federal holidays).
There are 105 weekend days in 1008.
Yes. 1008 is a leap year and has 366 days.
10 public holidays fall on weekdays in 1008.
How many working days in 1007 in USA (Federal holidays)? How many working days in 1009 in USA (Federal holidays)?